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Derivative of f(x) = x^3 at the point (2, 8)

User Airfang
by
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1 Answer

5 votes

Answer:

f'(x) = 12

Explanation:

f(x) = x^3

f'(x) = 3*x^(3-1)

f'(x) = 3x^2

f'(x) = 3(2)^2 ==> Plug in 2 for the x-value

f'(x) = 3(4)

f'(x) = 12

User Darryn Campbell
by
3.9k points