Question

What is the child’s speed at the bottom of the slide

Answer 1

Answer:

Step-by-step explanation:

The mass of the child, m = 22 kg

Height, h = 2.5 m

The child starts at rest

The initial velocity, u = 0

Workdone on the child, W = -381 J

The child's speed at the bottom of the slide is the final speed

Final speed, v = ?

Based on the principle of energy conservation

Kinetic Energy = Potential energy + Non-conservative workdone

`(1)/(2)mv^2=mgh+W`

Substitute m = 22, g = 9.8, h = 2.5, and W = -381 into the equation above

`\begin{gathered} (1)/(2)*22* v^2=(22*9.8*2.5)+(-381) \\ \\ 11v^2=539-381 \\ \\ 11v^2=158 \\ \\ v^2=(158)/(11) \\ \\ v^2=14.36 \\ \\ v=√(14.36) \\ \\ v=3.79\text{ m/s} \end{gathered}`