Question

p.m. and A patient's temperature was recorded at 8 a.m., 10 a.m., 4 6 p.m. The first, second, and fourth readings were 65° F, 85° F and 90° F, respectively. If the average of the four readings was 80° F, what was the third reading?

Answer 1

The value of the third reading is 80 F

`x=80^0F`

Step-by-step explanation:

Let x represent the value of the third reading.

The average of a set of data equals the sum of all the data divided by the number of data;

`\text{Average =}\frac{sum\text{ of data}}{\text{number of data}}`

Given;

Average = 80 F

Sum of data = 65+85+x+90

Number of data = 4

substituting we have;

`80=(65+85+x+90)/(4)`

solving for x;

`\begin{gathered} 80=(65+85+x+90)/(4) \\ 80*4=65+85+x+90 \\ 320=65+85+x+90 \\ 320=240+x \\ 320-240=x \\ x=80 \end{gathered}`

Therefore, The value of the third reading is 80 F

`x=80^0F`