Given equation

put x = 0 in equation (1) we get,

put x = 1 in equation (1) we get,

put x = -2 in equation (1) we get,

put x = 2 in the equation (1) we get,

The table will look like this,
to find the x intercept put y= 0 in the equation (1) and to find y intercept put x = 0 in the quation (1) we get ,
x - intercept = (-3,0)
y - intercept = (0,6)
to find the slope we use the formula,

consider two points , say (0,6) and (1,8)

Now, subsitute the above values in slope formula we get,

Thus, slope is 2