Let's solve the equation:
![\begin{gathered} \lvert x+2\rvert=0 \\ x+2=\pm0 \\ x=-2\pm0 \\ x=-2 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/nwyvwyq8dfoxrbioy8icb026iv0nccwo56.png)
Let's now solve the inequality:
![\begin{gathered} \lvert x+2\rvert\ge0 \\ x+2\ge0\lor x+2\leq0 \\ x\ge-2\lor x\leq-2 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/7supx7jpi7kcucj6p4q6ai4re669wobtmr.png)
Therefore the solution of the inequality is:
![(-\infty,-2\rbrack\cup\lbrack-2,\infty)](https://img.qammunity.org/2023/formulas/mathematics/college/r82dgg5n3mhxcy9hj0qcxuwkkuhuib4kid.png)
Once we know both solutions we conclude that:
The equation has one solution and the inequality have a range of solutions. Therefore the correct choice is the third option.