141k views
1 vote
Hi, can I receive tutoring on this problem please. It would be greatly appreciated.

Hi, can I receive tutoring on this problem please. It would be greatly appreciated-example-1
User Jonask
by
5.9k points

1 Answer

4 votes

The expression given is


2x^3+5x^2+6x+15

Arranging the expression into two groups


(2x^3+5x^2)+(6x+15)
\begin{gathered} \text{Factor out x}^2\text{ from }2x^3+5x^2 \\ =x^2(2x_{}+5) \end{gathered}

Factor out 3 from 6x + 15


=3(2x+5)

Then the expression is now resulted into


=x^2\mleft(2x+5\mright)+3\mleft(2x+5\mright)
\begin{gathered} \mathrm{Factor\: out\: common\: term\: }2x+5 \\ =\mleft(2x+5\mright)\mleft(x^2+3\mright) \end{gathered}

Hence, the factors of the expression are


\mleft(2x+5\mright)\mleft(x^2+3\mright)

User Angelene
by
5.6k points