To find the value of x, we have to know:
- The denominator can not be zero
- The radical must be zero or greater than zero
So, let's evaluate the numerator and the denominator
a)
![x+2\ge0](https://img.qammunity.org/2023/formulas/mathematics/college/35ngz8w2judvgnprs3m9oady81xm2a7uuj.png)
Subtracting 2 from both sides:
![\begin{gathered} x+2-2\ge0-2 \\ x\ge-2 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/i0xha2tai5gm8zmqgwliuycozi3eyhyc5e.png)
b)
![5-x>0](https://img.qammunity.org/2023/formulas/mathematics/college/xsmhj2ctwzbdcx4qc1okto6tnyh0dr6yhd.png)
Adding x to both sides:
![\begin{gathered} 5-x+x>0+x \\ 5>x \\ x<5 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/mdtq1u90a599qab8wiatt7svlhmlchwr96.png)
So, x must b greater or equal to 2 and lower than 5.
Answer:
![2\leq x<5](https://img.qammunity.org/2023/formulas/mathematics/college/w36oo50hqgteao98rnqjw8nk1q4q5gft84.png)