f(3) =f (3-1)^2 - 3
f(1) = 4
then
f(1) = f ((n-1)^2 - n)
4 = (-1 ^2) + 3
Now then find
f(n) = ((n-1)^2 - n)^2 + 3,. For n= 3
. = ((3-1)^2 - 3)^2 + 3
. = ( 2^2 - 3)^2 + 3
. = 4
Then answer is
f(3) = 4
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