Notice that the total probability is distributed in 8 minutes. Furthermore, the total probability has to be equal to 1, then:
![\begin{gathered} h\cdot8=1 \\ \Rightarrow h=(1)/(8)=0.125 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/n7juys1mtf5byxgt15w2vsm4lmnh5q8ghv.png)
Where h is the height of the distribution. The first answer is 0.125.
b) Notice that 16-13=3 min. Therefore, the probability we are looking for is:
![P(13<strong>The second answer is 0.375</strong><p>c) Notice that the probability for the bus to arrive before 15 minutes is:</p>[tex]P(X\le15)=(15-9)/(8)=(6)/(8)=0.75]()
Thus, the probability that will we wait more than 15 minutes is:
![P(X>15)=1-0.75=0.25](https://img.qammunity.org/2023/formulas/mathematics/high-school/768x6f2cwxi3axl1lnvjwskoeec6nwoiuy.png)
The third answer is 0.25
d) The probability that one will wait at most 15 minutes was found in the previous step:
![P(X\le15)=(15-9)/(8)=(6)/(8)=0.75](https://img.qammunity.org/2023/formulas/mathematics/high-school/1mwwzbyosfilzng7uj063yk94g4ffqqjf1.png)
The fourth answer is 0.75