Notice that the total probability is distributed in 8 minutes. Furthermore, the total probability has to be equal to 1, then:

Where h is the height of the distribution. The first answer is 0.125.
b) Notice that 16-13=3 min. Therefore, the probability we are looking for is:
![P(13<strong>The second answer is 0.375</strong><p>c) Notice that the probability for the bus to arrive before 15 minutes is:</p>[tex]P(X\le15)=(15-9)/(8)=(6)/(8)=0.75]()
Thus, the probability that will we wait more than 15 minutes is:

The third answer is 0.25
d) The probability that one will wait at most 15 minutes was found in the previous step:

The fourth answer is 0.75