Question

How many grams of carbon dioxide would be formed from a reaction of 0.315 grams glucose?C6H12O6 → 2 C2H6O + 2 CO2

Answer 1

0.154 g of CO2 (carbon dioxide).

Step-by-step explanation:

What is given?

Grams of glucose (C6H12O6) = 0.315 g.

Molar mass of glucose (C6H12O6) = 180 g/mol.

Molar mass of carbon dioxide (CO2) = 44 g/mol.

Chemical equation:

`C_6H_(12)O_6\rightarrow2C_2H_6O+2CO_2.`

Step-by-step solution:

First, we have to convert 0.315 g of glucose (C6H12O6) to grams using its given molar mass. The conversion will be:

`0.315\text{ g C}_6H_(12)O_6\cdot\frac{1\text{ mol C}_6H_(12)O_6}{180\text{ g C}_6H_(12)O_6}=0.00175\text{ moles C}_6H_(12)O_6.`

Now, you can see in the chemical equation that 1 mol of glucose (C6H12O6) reacted produces 2 moles of CO2, so the number of moles of CO2 that will produce 0.00175 moles of C6H12O6 based on this information is:

`0.00175\text{ moles C}_6H_(12)O_6\cdot\frac{2\text{ moles CO}_2}{1\text{ mol C}_6H_(12)O_6}=0.00350\text{ moles CO}_2.`

And the final step is to convert from 0.00350 moles of CO2 to grams using its given molar mass, so the calculation would be:

`0.00350\text{ moles CO}_2\cdot\frac{44\text{ g CO}_2}{1\text{ mol CO}_2}=0.154\text{ g CO}_2.`

The answer is that we will produce 0.154 g of CO2 (carbon dioxide) from 0.315 g of glucose.