Question

Find the equation of a line that passes through (-2,8) with a slope of 4.

Answer 1

Step 1:

We are to find the equation of a line that passes through (-2, 8) with slope of 4.

Step 2:

We use the formula below to solve this question;

`\begin{gathered} y-y_1=m(x-x_1) \\ _{} \\ \end{gathered}`
`\begin{gathered} \text{Where x}_{1\text{ }}\text{ = -2} \\ \text{and y}_1\text{ = 8} \\ Slope\text{ (m) = 4} \end{gathered}`

Step 3:

We are to substitute all these parameters into the formula?

`\begin{gathered} y-y_1=m(x-x_1) \\ y\text{ - 8 = 4 (x-(-2)}) \\ y-8\text{ = 4 (x + 2)} \\ y\text{ - 8 = 4x +8} \\ \text{Making y the subject of the formula;} \\ y\text{ = 4x +8+8} \\ y\text{ = 4x + 16} \end{gathered}`