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The length of the rectangle is 3 meters more than twice the width. The perimeter is 54 meters. find the dimension

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We are told that a rectangle has aparticular length L wich is 3 meters more than twice the rectangle's width W

So we can write this in mathematical terms as:

L = 2 W + 3

and also we can write an equation that takes into consideration the perimeter of the rectangle:

Perimeter = 54 meters = 2 L + 2 W

so we replace the expression for the length we got in the first equation into the second equation we typed:

54 = 2 (2 W + 3) + 2 W

54 = 4 W + 6 + 2 W

54 = 6 W + 6

subtract 6 from both sides

54 - 6 = 6 W

48 = 6 W

divide both sides by 6 to isolate W completely

W = 48 / 6

W = 8 meters

Now we can find what the length is by replacing this value we got for the width in the equation:

L = 2 W + 3

L = 2 * 8 + 3

L = 16 + 3 = 19

Then L = 19 m

and the width is W = 8 meters.

Dimensions : Length 19 m, and width 8 m

User Allyraza
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