Question

One inductor reduces the voltage from 240V to 12V, with an effective voltage of 10A at the primary winding and 180A at the secondary winding.The initial number of transformers is 5,000 spirals. A. Find the number of spirals in the average coil? B. Calculate the output of the transformer?

Answer 1

Given:

`\text{The primary voltage is V}_p=240\text{ V}`
`\text{The secondary voltage is V}_s=12\text{ V}`
`\text{The primary current is I}_p=10\text{ A}`

The initial number of tun is,

`n_p=5000`

A.

from the formula of transformer,

`\begin{gathered} (I_s)/(I_p)=(n_p)/(n_s) \\ \frac{180\text{ A}}{10\text{ A}}=(5000)/(n_s) \\ n_s=(5000*10)/(180) \\ n_s=278 \end{gathered}`

B.

Output of the transformer is,

`\begin{gathered} P_(out)=V_sI_s \\ =12\text{ V}*180\text{ A} \\ =2160\text{ Watt} \end{gathered}`

Hence the output power is 2160 Watt.