Question

I got a question for a school assignment if you guys could help me out k would appreciate it a lot please and thank you.

Answer 1

Step 1

The surface area of the square pyramid

= Sum of the area of the four triangular faces and the area of the square base.

Step 2

`\begin{gathered} \text{Area of the triangular face = }\frac{Base\text{ }*\text{ Height}}{2} \\ Base\text{ = 0.8 foot} \\ Height\text{ = 6 feet} \\ Area\text{ of the triangular face = }\frac{0.8\text{ }*\text{ 6}}{2}\text{ = 2.4 ft}^2 \\ Area\text{ of the four triangular faces = 4 }*\text{ 2.4 = 9.6 ft}^2 \\ Area\text{ of the square base = L}^2\text{ = 0.8}^2\text{ = 0.64} \end{gathered}`

Step 3

`Surface\text{ area of the square pyramid = 9.6 + 0.64 = 10.24 ft}^2`

Final answer

10.24 square feet