Question

An equation for the line through (-7, -8) that is parallel to y=-3/5x -7

Answer 1

Given:

The line passes through the point is (-7, -8) and parallel to the line

`y=-(3)/(5)x-7`

To find:

The equation of the line.

Step-by-step explanation:

Since the lines are parallel. So, the slope of the line is

`m=-(3)/(5)`

Using the point-slope formula,

`\begin{gathered} (y-y_1)=m(x-x_1) \\ y-(-8)=-(3)/(5)(x-(-7)) \\ y+8=-(3)/(5)(x+7) \\ y+8=-(3)/(5)x-(21)/(5) \\ y=-(3)/(5)x-(21)/(5)-8 \\ y=-(3)/(5)x-(21)/(5)-(40)/(5) \\ y=-(3)/(5)x-(61)/(5) \end{gathered}`

Hence, the equation of the line is,

`y=-(3)/(5)x-(61)/(5)`

Final answer:

The equation of the line is,

`y=-(3)/(5)x-(61)/(5)`