Question

What is the slope of the line that passes through the points (_5,0) and (-3,1)?

Answer 1

`\begin{gathered} \text{The equation of a straight line is} \\ y-y_1=\text{ }(y_2-y_1)/(x_2-x_1)(x-x_1) \end{gathered}`

Step 2 : Define parameters

`\begin{gathered} y_1=0 \\ y_2=1 \\ x_1=-5 \\ x_2=\text{ -3} \end{gathered}`

Step 3: Substitute the parameters into the equation

`\begin{gathered} \text{slope}=\text{ }(y_2-y_1)/(x_2-x_1) \\ \text{slope}=(1-0)/(-3-(-5)) \\ \text{slope = }(1)/(-3+5)=(1)/(2) \\ \text{slope}=\text{ }(1)/(2)\text{ or 0.5} \end{gathered}`