We have a right triangle.
We can write the Pythagorean theorem as:

We add the square of the legs and that is equal to the square of the hypotenuse.
Then, we can rearrange to solve for x as:
![\begin{gathered} x^2+3.9^2=11^2 \\ x^2=11^2-3.9^2 \\ x^2=121-15.21 \\ x^2=105.79 \\ x=\sqrt[]{105.79} \\ x\approx10.3 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/yalg8u42pek1e1mt1b6ccf8b0tp7e1j8np.png)
Answer:
We can write the Pythagorean theorem as x^2+3.9^2=11^2.
The value of x is approximately 10.3.