Question

What is a left-end behavior of the function f(x)=(x^2−e^x)/x

Answer 1

We have the next function

`f\mleft(x\mright)=(x^2-e^x)/(x)`

We need to calculate the lim when x tends to -inf

`\lim _(x\to-\infty)(x^2-e^x)/(x)=-\infty`

Then we have that the left end behavior is

`\: x\to\: -\infty\: ,\: f\mleft(x\mright)\to\: -\infty`