Question

Suppose kinetic energy is 4 joules of a moving object what will happen if we increase the speed twice

(guys pls show me the work out)​

Answer 1

The kinetic energy is 16 joules.

Step-by-step explanation:

Kinetic energy (E) is given by:

`E = (1)/(2)mv^(2)`

Where:

m: is the mass

v: is the speed

When the kinetic energy is 4 joules, the speed of the object is:

`v_(1)^(2) = (2E_(1))/(m) = (8)/(m)`

Now, if the speed is increased twice then we have:

`E_(2) = (1)/(2)mv_(2)^(2) = (1)/(2)m(2v_(1))^(2) = (1)/(2)m[4((8)/(m))] = 16 J`

Therefore, the kinetic energy is 4 times the initial value.

I hope it helps you!