Question

Write the equation in point-slope form of the line that passes through the given point with the given slope.

(-3/2,6) ; m = -1
m= -1
The equation of the line is

Answer 1

The point-slope form is
`y-y_1=m(x-x_1)`.

You need to substitute in the given slope and the given x-coordinate and y-coordinate:

`y - 6 = -1 (x-(-(3)/(2)))`

This cleans up to be:

`y - 6 = - (x+(3)/(2))`

Answer 2

`(\stackrel{x_1}{-(3)/(2)}~,~\stackrel{y_1}{6})\hspace{5em} \stackrel{slope}{m}\implies -1 \\\\\\ \begin{array}ll \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{6}=\stackrel{m}{-1}(x-\stackrel{x_1}{(-(3)/(2))})\implies y-6=-(x+(3)/(2))`