23.0k views
4 votes
SHOW WORK PLEASE

What are the solutions to y2 - 13y + 40 =0?
A. y = 5 and y = 8
B .Y=-5 and y = -8
C. y = 4 and y = 10
D. y = -4 and y = -10

1 Answer

2 votes
Ok so you know how to factor quadratics. Take the c and a values (the constant and number in front of x^2 or y in this case and multiply them) you get 40 so now you need to find factors of 40 that add up to negative 13. In this case -5 and -8. So you can rewrite the equation as (y-5) *(y-8) now set each part equal to 0 so y-5 =0 and y-8 =0. You will get y = 5 and y=8
User Durgesh Chaudhary
by
7.5k points