Question

If the area of a square is increased by 69%, then the side of the square is increased by what percent?

Answer 1

Percent Increase in measure of the side of a square = 30%

Explanation:

Let the measure of the side of a square = s

Area of the square = (Side)²

= s²

If the area of the square is increased by 69%

Area of the new square = s² + 69% of s²

= s² + 0.69s²

= 1.69s²

Therefore, measure of the side of the new square = √(Area of the square)

= √(1.69s²)

= 1.3s

Measure of side of the old square = s

Therefore, increase in measure of the square = 1.3s - s

= 0.3s

Percent increase in the measure of the side of the square

=
`\frac{\text{Increase in measure}}{\text{Measure of the side of the original square}}* 100`

=
`(0.3s)/(s)* 100`

= 30%