Question

Зу = 5х+12
2х-3у = - 12
Elimination

Answer 1

Explanation:

3y=5x+12

Answer 2

x = 0

y =4

Explanation:

Solving system of linear equations by elimination method:

3y = 5x + 12

5x + 12 = 3y

5x = 3y - 12

5x - 3y = -12 -------------------(I)

2x -3y = -12 -------------------(II)

Subtract the (II) equation from (I) equation,

(I) 5x - 3y = -12

(II) 2x - 3y = -12 {Now subtract}

- + = +

3x = 0

`\sf \boxed{\bf x = 0}`

Substitute x = 0 in equation (I)

5x - 3y = -12

0 - 3y = -12

-3y = -12

y = -12 ÷ (-3)

`\s \boxed{\bf y = 4}`