Question

The function fis defined by f: x→ ax² + b,

where a and b are constants.
Given that f(-2) = 2 and f(4) = 14, find the
values of a and b.

Answer 1

a = 1, b = -2

Explanation:

`a {( - 2)}^(2) + b = 2`

`a( {4}^(2) ) + b = 14`

4a + b = 2

16a + b = 14

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12a = 12

a = 1, and so b = -2