Question

2Fe + 0₂ → 2 FeO

write balanced half-reactions describing the oxidation and reduction that happen in this reaction.

Answer 1

`Oxidation half reaction: 2Fe - 4e^(-) -->2 Fe^(2+)`

`Reduction half reaction: O_(2) + 4e^(-) -->2O^(2-)`

`By adding, we get, 2Fe + O_(2) --> 2Fe^(2+) + 2O^(-2) which is ultimately 2Fe + O_(2) --> 2FeO`