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(3n³-15n² +21n-16)÷(n-2)

User MihaiV
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1 Answer

4 votes

Answer:


3n^2-9n+3-(10)/(n-2)

Explanation:


(3n^3 -15n^2+21n-16)/(n-2) \\ \\ =(3n^2(n-2)-9n^2+21n-16)/(n-2) \\ \\ =(3n^2(n-2)-9n(n-2)+3n-16)/(n-2) \\ \\ =(3n^2(n-2)-9n(n-2)+3(n-2)-10)/(n-2) \\ \\ =3n^2-9n+3-(10)/(n-2)

User Nachik
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