Answer:
5x+2y=6 let it be equation no.1
then,
equation no.1 is parallel to the line which point is (2,-5)
5x+2y+k=0 let it be equation no.2
then,
equation no.2 passes through a point (2,-5)
5x2+2x(-5)+k =0
10+(-10)+k=0
0+k=0
k=0
putting the value of k in equation no.2 we get,
5x+2y+0=0let it be equation no.3
then, the slope of equation no.3 is -5/2