Question

8. As she climbs a hill, a cyclist slows down from 25 mi/hr to 6 mi/hr in 10 seconds. What is her deceleration?

Answer 1

See below

Step-by-step explanation:

Change in velocity / change in time = acceleration

25 mi /hr = 36.6 ft/sec

6 mi/hr = 8.8 ft/sec

19 ft/sec / 10 sec = 1.9 ft/s^2 is decceleration