Question 1

Math: You may need a graphing calculator

Question 2

The values of x are = 0, -2, -3

x^3 + 5x^2 + 6x = 0

x^3 + 5x^2 + (2 * 3)x = 0

x ((x^3)/(x) + (5x^2)/(x) + (2*3x)/(x)) = 0

x(x^(3-1) +5x^(2-1)+2*3) = 0

x(x^2+5x+6)=0

$\left \{ {{x=0} \atop {x^2+5x+6=0}} \right.$

$\left \{ {{x=0} \atop {x((x^2)/(x) + (2x)/(x)) + 3((3x)/(3) + (2*3)/(3)) =0 }} \right$

$\left \{ {{x=0} \atop {x(x^(2-1) +2) + 3(x+2)=0}} \right.$

$\left \{ {{x=0} \atop {x(x+2)+3(x+2)=0}} \right.$

$\left \{ {{x=0} \atop {(x+2) ((x(x+2))/(x+2)+ (3(x+2))/(x+2))=0 } \right.$

$\left \{ {{x=0} \atop {(x+2) (x+3) =0}} \right.$

$\left \{ {{ x=0} \atop {x+2=0}} \atop {x+3=0}} \right.\\\\$

$\left \{ {{ x=0} \atop {(x+2) + (-2) = -2}} \atop {(x+3) + (-3)=-3}} \right.\\\\$

$\left \{ {{ x=0} \atop {x+2 -2 = -2}} \atop {x+3 -3 = -3}} \right.\\\\$

$\left \{ {{ x=0} \atop {x=-2}} \atop {x=-3}} \right.\\\\$

x = (0, -2, -3)

Answer: The values of
x=[0], [-2], [-3]

Please log in or register to add a comment.

Please log in or register to answer this question.