Answer:The empirical formula is
C
4
H
11
O
2
.
Step-by-step explanation:First, we calculate the masses of
C
and
H
from the masses of their oxides (
CO
2
and
H
2
O
).
Mass of C
=
1.900
g CO
2
×
12.01 g C
44.01
g CO
2
=
0.5185 g C
Mass of H
=
1.070
g H
2
O
×
2.016 g H
18.02
g H
2
O
=
0.1197 g H
Mass of C + Mass of H
=
0.5185 g + 0.1197 g
=
0.6382 g
This is less than the mass of the sample.
The missing mass must be caused by
O
.
Mass of O = 0.9827 g - 0.6382 g = 0.3445 g