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A cannon ball is launched from the edge of a cliff that is 6 m above the ground. It has a horizontal velocity of 10.2 m/s. It takes 3.7 s for the cannonball to reach the ground. How far from the cliff
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A cannon ball is launched from the edge of a cliff that is 6 m above the ground. It has a

horizontal velocity of 10.2 m/s. It takes 3.7 s for the cannonball to reach the ground.
How far from the cliff does it land?
Record your answer to the nearest hundredth.

User Nigel Sampson
by
7.8k points

1 Answer

7 votes

Answer:

Sh = Vh t horizontal distance traveled

Sh = 10.2 m/s * 3.7 s = 37.74 m

User Camilo Acosta
by
7.6k points
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