Register
A cannon ball is launched from the edge of a cliff that is 6 m above the ground. It has a horizontal velocity of 10.2 m/s. It takes 3.7 s for the cannonball to reach the ground. How far from the cliff
175k views
3 votes
A cannon ball is launched from the edge of a cliff that is 6 m above the ground. It has a

horizontal velocity of 10.2 m/s. It takes 3.7 s for the cannonball to reach the ground.
How far from the cliff does it land?
Record your answer to the nearest hundredth.

User Nigel Sampson
by
5.1k points

1 Answer

7 votes

Answer:

Sh = Vh t horizontal distance traveled

Sh = 10.2 m/s * 3.7 s = 37.74 m

User Camilo Acosta
by
5.0k points
Ask a Question
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

5.1m questions

6.7m answers

Other Questions

A space shuttle is approaching the surface of the moon to land. It approaches the moons surface with an initial velocity of 28m/s and is slowing at a rate of -2m/s^2. Show all work and units for problems.
________ is a measure of the internal energy that has been absorbed or transferred from one body to another, often due to a difference in temperature.
5. What happens to the arrangement of water molecules as ice melts? A Molecules gain enough energy to escape as vapor. B Molecules release enough energy to escape as vapor. C Molecules gain enough energy
A projectline is shot from the edge of a cliff 100 m above the ground with intial speed 10 m/s at an angle 30 with the horizontal. 1) determine the time taken by the projectile motion to hit the ground
A 2.0-N force acts horizontally on a 10-N block that is initially at rest on a horizontal surface. The coefficient of static friction between the block and the surface is 0.50. Suppose that the block now
Link Copied!