Question

2) a) The equation for the formation of ammonia from nitrogen and hydrogen is shown

below. What is the form of the equilibrium constant Ke? b) Calculate Kc if the
equilibrium mixture contains 0.040M NH3, 0.60M H₂ and 0.20M N2.
3H2(g) + N2(g) = 2NH³(g)

Answer 1

A Kc of 0.022 is found, which means that the system contains mostly reactants for the conditions of this reaction. The equation is Kc = [NH3]^2/([H2]^2[N2]).

Step-by-step explanation:

The equilibrium constant equation, Kc, for for a reaction

aA + bB = cC + dD

is given by

Kc = ((C^c)(D^d))/((A^a)(B^b)

The reaction of hydrogen with nitrogen to form ammonia is

3H2(g) + N2(g) = 2NH3(g)

The equilibrium constant would be:

Kc = [NH3]^2/([H2]^2[N2])

The equilibrium constant, Kc, for this mixture is:

Kc = (0.040M]^2/((0.60M)^2 (0.20M)

Kc = (0.0016)/(0.072)

Kc = 0.022

A Kc < 1 means that the system contains mostly reactants.