Question

It’s a two part for one question. Numbers 14 and 15 please

Answer 1

We are given a capacitor with a capacitance of 25 micro-farads. To determine the lower limit we will use the tolerance of -15%, and use the following relationship:

`l=25\mu F-25\mu F*15\%`

To multiply by 15% we multiply by 15/100, like this:

`l=25\mu F-25\mu F*(15)/(100)`

Solving the operations:

`l=21.25\mu F`

Therefore, the lower limit is 21.25 micro-farads.

Now, we calculate the upper limit using the 75% tolerance, like this:

`U=25\mu f+25\mu F*(75)/(100)`

Solving the operations:

`U=43.75\mu F`

Therefore, the upper limit is 43.75 micro-farad.