Answer:
The weight of the rocket before entry is

The rate of the rocket burn given is

Let the time for the burnout be represented as

The weight of the rocket to be burnt out will be calculated using the formula below

Burn out means the weight of the rocket is reducing so there will be a negative value

Hence,
The equation of the weight as a function of t will be

Hence,
The final answer is w(t) = -2t + 5300