Question

A child pushes, with a constant force, a merry-go-round with a radius of 2.5 m, from rest to an angular velocity of 3rad/s in 8s. What is the merry-go-round's centripetal acceleration at this point?

Answer 1

Given:

The radius of the merry-go-round, r=2.5 m

The final angular velocity of the merry-go-round, ω=3 rad/s

The time period, t=8 s

To find:

The centripetal acceleration of the merry-go-round when it has the angular velocity is 3 rad/s

Step-by-step explanation:

The centripetal acceleration is given by the equation,

`a_c=\omega^2r`

On substituting the known values,

`\begin{gathered} a_c=3^2*2.5 \\ =22.5\text{ m/s}^2 \end{gathered}`

Final answer:

The centripetal acceleration of the merry-go-round at the required point is 22.5 m/s²