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Find the exact value of sin G.A. √1010B. 3√1010C. 4√10D. 160

Find the exact value of sin G.A. √1010B. 3√1010C. 4√10D. 160-example-1
User FerCa
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1 Answer

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Given the Right Triangle EFG, you know that:


\begin{gathered} EF=4 \\ EG=12 \end{gathered}

By definition:


sin\theta=(opposite)/(hypotenuse)

Since, in this case:


\theta=G

You can identify that:


\begin{gathered} opposite=EF=4 \\ hypotenuse=FG \end{gathered}

In order to find the hypotenuse of the Right Triangle, you need to use the Pythagorean Theorem, which states that:


c=√(a^2+b^2)

Where "c" is the hypotenuse, and "a" and "b" are the legs of the Right Triangle.

You can set up that:


\begin{gathered} c=FG \\ a=EG=12 \\ b=EF=4 \end{gathered}

Therefore:


FG=√(12^2+4^2)=4√(10)

Now you can determine that:


sinG=(4)/(4√(10))

Simplify:


sinG=(1)/(√(10))

You can multiply the numerator and the denominator by:


√(10)

In order to Rationalize the denominator:


sinG=(1\cdot√(10))/(√(10)\cdot√(10))
sinG=(1\cdot√(10))/((√(10))^2)
sinG=(√(10))/(10)

Hence, the answer is: Option A.

User Tom Swirly
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