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write an expression in simplest form for the perimeter of a right triangle with leg lengths of 12a^4 and 16a^4an expression is____a^4

1 Answer

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Given the lengths of the right triangle:


\begin{gathered} 12a^4^{} \\ \text{and } \\ 16a^4 \end{gathered}

To find the perimeter, use the formula:


P=a+b+\sqrt[]{a^2+b^2}

Thus, we have:


P=12a^4+16a^4+\sqrt[]{(12a^4)^2+(16a^4)^2}
\begin{gathered} P=28a^4+\sqrt[]{144a^4+256a^4} \\ P=28a^4+\sqrt[]{400a^4} \\ P=28a^4+20a^4 \\ P=48a^4 \end{gathered}

Therefore, the expression is:


48a^4

User Shawn Spencer
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