Question

If a cat is thrown upward at an angle with an initial velocity of 11 m/s and a horizontal velocity of 8 m/s, what is the cats impact speed when he lands?

Answer 1

13.6 m/s

Explanation:

The speed of the impact would be the resulting velocity between the initial velocity (which according to the statement is a vertical velocity) and the horizontal velocity.

Now we know the vertical and horizontal components of velocity we can find the resultant by means of the Pythagorean theorem. Using Pythagoras we can say that:

`\begin{gathered} c^2=a^2+b^2 \\ \text{ In this case:} \\ V^2_r=V^2_v+V^2_h \\ \text{Replacing:} \\ V^2_r=11^2+8^2 \\ V^2_r=121+64 \\ V_r=\sqrt[]{185} \\ V_r=13.6\text{ m/s} \end{gathered}`

Therefore, the impact speed is 13.6 m/s