A = P ( 1 + r )^t
Given A = $2000 , r = 3% = 0.03
so, after 2 years t = 2
A = 2000 * ( 1 + 0.03)^2 = $2,121.8
so, the total after 2 years = $2,121.8
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How much money should be invested today to accumulate to $10,000 in 10 years at 4.5% compounded monthly? (Simplify your answer. Round to the nearest cent as needed)
so, A = $10,000
r = 4.5% = 0.045
t = 10 years = 10 * 12 = 120 months
So, A = P (1 + r/n)^t ,,, n = 12
10,000 = P ( 1 + 0.045/12)^120
10,000 = P * 1.567
P = 10,000/1.567 = 6,381.65 ( to the nearest cent )
so, the money should be invested = $6,381.65