Question

each triangle face of the pyramid of peace in Kazakhstan is made up of 25 smaller equilateral triangles these triangle have measurements as shown in the diagram what is the area of one of the smaller equilateral triangle?

Answer 1

we know that

The area of any triangle is equal to

A=(1/2)bh

in this problem we have

b=12 m

h=10.4 m

substitute the given values

A=(1/2)(12)(10.4)

A=62.4 m^2