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U cubed + 3u squared minus 6 divided by u + 4

User Opsimath
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1 Answer

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The first step is to write the division in an equation form:

Now find a term to multiply u+4 that can be canceled with u^3 (the first term) and so for each term


(u^3+3u^2-6)/(u+4)

Now the answer is


u^2+3u-16+(58)/(u+4)

U cubed + 3u squared minus 6 divided by u + 4-example-1
U cubed + 3u squared minus 6 divided by u + 4-example-2
U cubed + 3u squared minus 6 divided by u + 4-example-3
U cubed + 3u squared minus 6 divided by u + 4-example-4
U cubed + 3u squared minus 6 divided by u + 4-example-5
User Sheler
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