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If u = 5 inches, v = 7 inches, w = 4 inches, x = 7 inches, y = 12 inches, and z = 4 inches, then what is the perimeter of the object?

If u = 5 inches, v = 7 inches, w = 4 inches, x = 7 inches, y = 12 inches, and z = 4 inches-example-1

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The perimeter of a figure is the sum of all its sides.

In the given figure, we have two unknown sides, let's call them a and b:

Also, we can say that:


\begin{gathered} w+a+u=y\text{ Equation 1} \\ b+x=v+z\text{ Equation 2} \end{gathered}

By replacing the known values, we can find a and b:


\begin{gathered} a=y-w-u \\ a=12-4-5=12-9=3inches \\ \\ b=v+z-x \\ b=7+4-7=4inches \end{gathered}

So, the perimeter is given by:


\begin{gathered} P=a+b+u+v+w+x+y+z \\ P=3+4+5+7+4+7+12+4 \\ P=46\text{ inches} \end{gathered}

The answer is B. 46 inches

If u = 5 inches, v = 7 inches, w = 4 inches, x = 7 inches, y = 12 inches, and z = 4 inches-example-1
User Robin Varghese
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