Given the following equation:
![4-(2x-3)=3](https://img.qammunity.org/2023/formulas/mathematics/high-school/gz4sburdfdevvfb40uuxhxs1dv1qpyh3b9.png)
You can solve for "x" by following these steps:
1. You must distribute the negative sign of the left side of the equation:
![4-2x+3=3](https://img.qammunity.org/2023/formulas/mathematics/high-school/awx4tpx5yht55q608lr40dz2sdvozct1qm.png)
2. Now you need to add the like terms of the left side of the equation:
![7-2x=3](https://img.qammunity.org/2023/formulas/mathematics/high-school/309w1wkvtl63r9malwvwinzoglatcibl9p.png)
3. Apply the Subtraction property of equality by subtracting 7 from both sides of the equation:
![\begin{gathered} 7-2x-(7)=3-(7) \\ -2x=-4 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/guweikckv9mu57xblu4wnf9x8p23k50mgo.png)
4. Finally, you can apply the Division property of equality by dividing both sides of the equation by -2:
![\begin{gathered} (-2x)/(-2)=(-4)/(-2) \\ \\ x=2 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/lc5vntyexk85htjvjczml6ktp16uhmt4n0.png)
The answer is:
![x=2](https://img.qammunity.org/2023/formulas/mathematics/college/6ij5lvx45qkbn22ki7umkb6rdcr9rugcgd.png)