Question

Given this equation: 3 MgCl2 + 2 Al → 3 Mg + 2 AlCl3, if 2.3 moles of magnesium chloride reacted how many moles of aluminum chloride are produced?

Answer 1

The number of moles of aluminum chloride is 1.533 moles

Explanation:

Given information

Number of moles of Magnesium chloride = 2.3 moles

The next thing is to write the balanced equation of the reaction

`3MgCl_2\text{ + 2Al }\rightarrow3Mg+2AlCl_3`

From the balanced chemical reaction equation, you will see that 3 moles of Magnesium chloride react with 2 moles of aluminum to produce 3 moles of magnesium and 2 moles of aluminum chloride.

The next step is to find the number of moles of aluminum chloride in the reaction using a stoichiometry ratio.

Let x represents the number of moles of aluminum chloride

From the chemical reaction equation,

3 moles of magnesium chloride give 2 moles of aluminum chloride

2. 3 moles of magnesium will give x moles of aluminum chloride

The above statement can be translated below as

`\begin{gathered} 3\text{ }\rightarrow\text{ 2} \\ 2.3\text{ }\rightarrow\text{ x} \\ \text{Cross multiply} \\ 3\cdot\text{ x = 2 }\cdot\text{ 2.3} \\ 3x\text{ = 4.6} \\ \text{Divide both sides by 3} \\ (3x)/(3)\text{ = }(4.6)/(3) \\ x\text{ = 1.5333 moles} \end{gathered}`

Since x represents the number of moles of aluminum chloride, therefore, the number of moles of aluminum chloride is 1.533 moles