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A sled and rider with a combined weight of 70.0 kg are at rest on the top of a hill 11.0 m high. (Enter your answers in J.)(a)What is their total energy at the top of the hill? answer in______J(b)Assuming there is no friction, what would the total energy be on sliding halfway down the hill? answer in_______J(c)What would the total energy be at the bottom of the hill? answer in_________J

User Ddavidad
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We will ahve the following:

a)


\begin{gathered} E=mgh \\ \\ \Rightarrow E=(70.0kg)(9.8m/s^2)(11.0m)\Rightarrow E=7546J \end{gathered}

So, the total energy will be 7546 J.

b) The total energy halfway must also be the same, but half of it will be kinetic energy and half potential energy.

c) The total energy at the bottom must be the same, but this time it will be all kinetic energy.

User Cugomastik
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