How many distinct proper subsets are there of the set N={9,41,64,12,38,59,23}

Question

asked Jan 13, 2023 116k views

1 Answer

Boldizsar · Answer 1 · 2023-01-17T06:00:42+0000

Given:

N={9,41,64,12,38,59,23}

To find the number of distinct proper subsets, use the formula below:

$2^{n\text{ }}-\text{ 1}$

Where n is the number of values in the set.

Here, n = 7

The number of distinct proper subsets are:

$\begin{gathered} 2^7\text{ - 1 } \\ =\text{ (2}\ast2\ast2\ast2\ast2\ast2\ast2)-1 \\ =\text{ 128 - 1} \\ =\text{ 127} \end{gathered}$

Therefore, there are 127 distinct proper subsets