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Are the lines created using the given points perpendicular?L1: (1,2), ( 3,1) and L2: (0,-1), (2,0)

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Answer:


No,\text{ they are not}

Step-by-step explanation:

To check for this, we have to get the slope of the two lines

The slope of a line can be calculated using the formula:


m\text{ = }(y_2-y_1)/(x_2-x_1)

where (x1,y1) are the coordinates of the first point and (x2,y2) are the coordinates of the second

Mathematically, we have the slope of the first as follows:


m\text{ = }(1-2)/(3-1)\text{ = -}(1)/(2)

For the second line, we have it that:


m\text{ = }(0+1)/(2-0)\text{ = }(1)/(2)

When two lines are perpendicular, the product of their slopes is equal to -1

We have it that:


(1)/(2)*(-(1)/(2))\text{ = -}(1)/(4)

This shows that the two lines are not perpendicular

User Marlan
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