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Write an equation of a line that passes through the given point and has the given slope.the correct blanks for the value of m and b.1.(3, -3), slope 3

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For this you can use the equation point slope, that is,


\begin{gathered} y-y_1=m(x-x_1) \\ \end{gathered}

Where,


\begin{gathered} m\colon\text{ slope of the line} \\ (x_(1,)y_1_{})\colon\text{ coordinates of the given point through which the line passes} \end{gathered}

So, you have


\begin{gathered} y-(-3)=3(x-3) \\ y+3=3x-9 \\ \text{ Substract 3 from both sides of the equation} \\ y+3-3=3x-9-3 \\ \text{Therefore, the equation of the line is} \\ y=3x-12 \end{gathered}

User Zahid M
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