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Yea I do it on my own but it was a goodFactor:

Yea I do it on my own but it was a goodFactor:-example-1
Yea I do it on my own but it was a goodFactor:-example-1
Yea I do it on my own but it was a goodFactor:-example-2
User Manofsins
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1 Answer

7 votes

Answer::


7m^2n^2(2m^6n^3-1)

Explanation:

Given the expression:


14m^8n^5-7m^2n^2

7m²n² is a common factor of the two terms.

Factor it out by dividing each of the terms to get the remainders:


14m^8n^5-7m^2n^2=7m^2n^2\mleft((14m^8n^5)/(7m^2n^2)-(7m^2n^2)/(7m^2n^2)\mright)

This then gives:


\begin{gathered} =7m^2n^2\mleft((7*2* m^2* m^6* n^2* n^3)/(7m^2n^2)-(7m^2n^2)/(7m^2n^2)\mright) \\ =7m^2n^2((7m^2n^2*2* m^6* n^3)/(7m^2n^2)-1) \\ =7m^2n^2(2m^6n^3-1) \end{gathered}

The factored form of the expression is:


7m^2n^2(2m^6n^3-1)

User Qodeninja
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