Question

Solve each system by substitution How can you solve a system of linear equation by using substitution

Answer 1

(3, -2)

Explanation:

Solving for x in the second equation gives

`x=-2y-1`

Putting this into the first equation gives

`2(-2y-1)+3y=0`

Expanding the left-hand side gives

`-4y-2+3y=0`
`-y-2=0`
`\boxed{y=-2.}`

With the value of y in hand, we put it in x + 2y = -1 to get

`x+2(-2)=-1`
`x-4=-1`

adding 4 to both sides gives

`\boxed{x=3.}`

Hence, the solution to the system is (3, -2) and it can be verified by plotting the graph.